&line2=\mathrm{Solution:\:}-\frac{9}{2-9x} "What is the derivative of y=ln(2-9x) ?")
What is the derivative of y=ln(2-9x) ?
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)}&line2=\mathrm{Solution:\:}y=\frac{\ln(x)}{\ln(2)}%2Bc_{1} "What is the solution for (dy)/(dx)= 1/(x(ln(2))) ?")
What is the solution for (dy)/(dx)= 1/(x(ln(2))) ?
Answered: Find the first partial derivatives of… | bartleby
SOLVED:In Exercises 37 and 38, solve for y. ln(y-1)-ln2=x+lnx
SOLVED: 2,4,6,8 please EXERCISE SET 3.2 1-26 Find dy/dx. 1. y=ln 5x 3 3.y = ln[1+ x| 5.y = ln|x2 - 1| 4. y = ln(2 + vx) 6.y= ln|x3- 7x2- 3
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