sin^2theta+sin^2(pi/6)^c+sin^2(pi/3)^c+sin^2(pi/2)^c
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![sin(pi/2-x) + sin(pi-x)]^2+[(cos((3pi)/2-x)+cos(2pi-x)]^2=](https://d10lpgp6xz60nq.cloudfront.net/ss/web/63533.jpg "sin(pi/2-x) + sin(pi-x)]^2+[(cos((3pi)/2-x)+cos(2pi-x)]^2=")
sin(pi/2-x) + sin(pi-x)]^2+[(cos((3pi)/2-x)+cos(2pi-x)]^2=
%CF%80}{2})&line2=\mathrm{Solution:\:}\sin(\frac{2%CF%80n-%CF%80}{2}) "sin(((2n-1)pi)/2)")
sin(((2n-1)pi)/2)
%2B\cos(\frac{2%CF%80}{2})&line2=\mathrm{Solution:\:}-1 "sin((2pi)/2)+cos((2pi)/2)")
sin((2pi)/2)+cos((2pi)/2)
sin^(2)pi/6+cos^(2)pi/3-tan^(2)pi/4=-1/2` - YouTube
&line2=\mathrm{Solution:\:}1 "sin(2pi+pi/2)")
sin(2pi+pi/2)
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ordinary differential equations - $\int_{-2\pi}^{2\pi}(1−u_0(x))\sin(x/2)(\delta(x + π) + \delta(x−π))\mathrm{d}x$ - Mathematics Stack Exchange
